The potential energy of a particle varies with distance $x$ from a fixed origin as $U\, = \,\frac{{A\sqrt x }}{{{x^2} + B}}$ Where $A$ and $B$ are dimensional constants then find the dimensional formula for $A/B$
The potential energy of a particle varies with distance $x$ from a fixed origin as $U\, = \,\frac{{A\sqrt x }}{{{x^2} + B}}$ Where $A$ and $B$ are dimensional constants then find the dimensional formula for $A/B$
- A
${M^2}{L^1}{T^{ - 2}}$
- B
${M^1}{L^{3/2}}{T^{ - 2}}$
- C
${M^0}{L^{1/5}}{T^{ - 3}}$
- D
${M^2}{L^{2/2}}{T^{ - 3}}$
Similar Questions
A physcial quantity $x$ depends on quantities $y$ and $z$ as follows: $x = Ay + B\tan Cz$, where $A,\,B$ and $C$ are constants. Which of the following do not have the same dimensions
A physcial quantity $x$ depends on quantities $y$ and $z$ as follows: $x = Ay + B\tan Cz$, where $A,\,B$ and $C$ are constants. Which of the following do not have the same dimensions
The pair having the same dimensions is
The pair having the same dimensions is
The force is given in terms of time $t$ and displacement $x$ by the equation
${F}={A} \cos {Bx}+{C} \sin {Dt}$
The dimensional formula of $\frac{{AD}}{{B}}$ is -
The force is given in terms of time $t$ and displacement $x$ by the equation
${F}={A} \cos {Bx}+{C} \sin {Dt}$
The dimensional formula of $\frac{{AD}}{{B}}$ is -
- [JEE MAIN 2021]
If $\mathrm{E}$ and $\mathrm{G}$ respectively denote energy and gravitational constant, then $\frac{\mathrm{E}}{\mathrm{G}}$ has the dimensions of :
If $\mathrm{E}$ and $\mathrm{G}$ respectively denote energy and gravitational constant, then $\frac{\mathrm{E}}{\mathrm{G}}$ has the dimensions of :
- [NEET 2021]
Dimensions of coefficient of viscosity are
Dimensions of coefficient of viscosity are
- [AIIMS 1993]